Question

Find deffence between the first two prime numbers

Answer 1

Suppose that the difference between two odd primes a=2n+1a=2n+1 and b=2m+1b=2m+1 is an odd prime, cc.

a−b=c⟹(2n+1)−(2m+1)=c⟹2(n+m)=c
a−b=c⟹(2n+1)−(2m+1)=c⟹2(n+m)=c
Therefore, 2|(a−b)2|(a−b), a contradiction.

It is therefore impossible for the difference of two odd primes to be an odd. This means that the difference of two odd primes must be even. The only even prime is 2.

So, if the difference of two odd primes is a prime, then it must be two.

Answer 2

hi...

here is your answer:

we now that 1st prime number is 2
and 2nd is 3

difference= 3-2

=1


hope u get ur answer!!!!