Question

find density of a handful of sand having a mass of 208g and it displaces a volume of 80 ml of water

Answer 1

Answer:- The density of metal is, 2.6 g/ml or $2600kg/m^3$

Solution : Given,

Mass of sand = 208 g

First we have to calculate the volume of sand

Volume of sand = volume of water displaced= 80 ml

Now we have to calculate the density of metal.

Formula used :

$Density=\frac{Mass}{Volume}$

Now put all the given values in this formula, we get the density of metal.

Density=$\frac{208g}{80ml}=2.6g/ml$

Therefore, the density of metal is, 2.6 g/ml or $2600kg/m^3$       $(1 gcm^{-3}=1000kgm^{-3}$

Answer 2

Explanation:

Answer:- The density of metal is, 2.6 g/ml or 2600kg/m^32600kg/m

3

Solution : Given,

Mass of sand = 208 g

First we have to calculate the volume of sand

Volume of sand = volume of water displaced= 80 ml

Now we have to calculate the density of metal.

Formula used :

Density=\frac{Mass}{Volume}Density=

Volume

Mass

Now put all the given values in this formula, we get the density of metal.

Density=\frac{208g}{80ml}=2.6g/ml

80ml

208g

=2.6g/ml

Therefore, the density of metal is, 2.6 g/ml or 2600kg/m^32600kg/m

3

(1 gcm^{-3}=1000kgm^{-3}(1gcm

−3

=1000kgm

−3