Question

find derivative of sin√3x

Answer 1

The derivative of
$\bf \: \: \: \sin( \sqrt{3} x) \: \: is \: \:$


$= > \frac{d}{dx} ( \sin( \sqrt{3}x ) = \sqrt{3} \cos( \sqrt{3}x )$
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Answer 2

$\frac{d}{dx} sin \sqrt{3x}$
$cos \sqrt{3x} \frac{d}{dx} \sqrt{3x}$
$cos \sqrt{3x} \frac{1}{2} \frac{1}{ \sqrt{3x} } 3$
$\frac{1}{2} \frac{1}{ \sqrt{3x} }cos \sqrt{3x}$