Find difference of zeroes of polynomial 1/2x^2-3x+2
Answers
Answered by
1
⭐⭐Hello friend..Ur answer is here⤵⤵
⚫ 1/2x^2-3x+2
let the zeroes are a and b
➡ a+b= -(-3)/1/2
➡ a+b=6
➡Now ab=2/(1/2)
➡ ab=4
Now the difference is...
➡(a-b)^2=(a+b)^2-4ab
➡(a-b)^2=6^2-4×4
➡ (a-b)^2=36-16
➡(a-b)=root20
I HOPE IT IS HELPFUL TO YOU ☺
⚫ 1/2x^2-3x+2
let the zeroes are a and b
➡ a+b= -(-3)/1/2
➡ a+b=6
➡Now ab=2/(1/2)
➡ ab=4
Now the difference is...
➡(a-b)^2=(a+b)^2-4ab
➡(a-b)^2=6^2-4×4
➡ (a-b)^2=36-16
➡(a-b)=root20
I HOPE IT IS HELPFUL TO YOU ☺
Similar questions