Question

Find discrimant of x2 + 7x + 10 = 0
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Answer 1

x²+7x+10=0

★On comparing with ax²+bx+c=0,

a=1,b=7 and c=10

★Applying the Discriminant formula,

D=b²-4ac

=(7)²-4(1)(10)

=49-40

→D=9

As D>0,the roots are real and distinct in nature

Answer 2

Step-by-step explanation:

${x}^{2} + 7x + 10$

Discriminant find

$d = {b}^{2} - 4ac \\ {(7)}^{2} - 4(1)(10) \\ = 49 - 40 \\ = 9 \\ discriminant = \sqrt{d } \\ \sqrt{9 } \\ = 3$

It is a real root (as Discriminant equal more than zero)

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