Question

Find discriminant 2x=2x^2-8

Answer 1

2x² - 2x - 8 = 0

$d = \sqrt{ {b}^{2} - 4ac } \\ \: \: \: = \sqrt{ {( - 2)}^{2} - 4 \times 2 \times - 8 } \\ \: \: \: = \sqrt{4 + 64} = \sqrt{68} = \sqrt{4 \times 17} \\ \: \: \: = 2 \sqrt{17}$

Hope this is helpful to you

Pls mark as brainliest

Follow me and I'll follow you back