Question

find discriminant of x^2-1/2x-4=0

Answer 1

Hope you are find your answer.

Thanks

Answer 2

${x}^{2} - \frac{1}{2} x - 4 = 0 \\ \\ multiplying \: throughout \: by \: 2 \\ we \: get \\ \\ 2 {x}^{2} - x - 8 = 0 \\ 2 {x}^{2} + ( - 1)x + ( - 8) = 0 \\ \\ on \: comparing \: this \: equation \: to \: the \\ general \: form \: i.e \: a {x}^{2} + bx + c = 0 \\ \\ a = 2 \: \\ b = - 1 \\ c = - 8 \\ \\now \\ discriminant \\ = {b}^{2} - 4ac \\ = {( - 1)}^{2} - 4(2)( - 8) \\ = 1 + 64 \\ = 65$

Hence, the discriminant of the given equation is 65.