Find distance between p(-6,-1,-5)
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1
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sorry i not like maths i am sorry
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0
Answer:
(X1, y1) = (-6,7)
(x2, y2) = (-1, -5)
pq = \ sqrt {(x2 - X1) {} ^ 2} + (y2 - y1) {} ^ {2}} \\ \\ pq = \ sqrt {(1 - (- 6)) {} {२} + (- ५ - {) {} ^ २}} \\ \\ pq = \ sqrt {(५) {} ^ २ २} + (- १२) {} ^ {२}} \\ \ _ \ pq = \ sqrt {25 + 144} \\ \\ pq = \ sqrt {169} \\ \\qq = 13
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