Math, asked by vikashshandilya234, 11 months ago

find distance from origins p(4,3)​

Answers

Answered by RAHULSEN504
2

Answer:

Distance=

 \sqrt{(y2 - y1)^{2} + (x2 - x1) ^{2}  }  \\  =  \sqrt{(4 - 0) ^{2} + (3 - 0) ^{2}  }  \\  =  \sqrt{4 ^{2}  + 3 ^{2} }  \\  =  \sqrt{16 + 9}  \\  =  \sqrt{25}  = 5

Therefore, the distance is 5 units

Answered by siddhibhatia150304
2

Answer:

Let the point at the origin be O

Since the point is at the origin, it's coordinates will be (0,0).

Applying distance formula

op =  \sqrt{(x2 - x1) {}^{2}  + (y2 - y1) {}^{2} }

op =  \sqrt{(4 - 0) {}^{2} + (3 - 0) {}^{2}  }

op =  \sqrt{4 {}^{2} + 3 {}^{2}  }

op =  \sqrt{16 + 9}

op =  \sqrt{25}

op = 5 \: units

Therefore the distance of point P from the origin is 5 units.

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