Question

Find distance of point (1,7) from y-axis

Answer 1

7 Unit is distance from Y-axis

Hope it will help you ❤️

Answer 2

Line perpendicular to the line x−y=2 and passing through point (7,1) will be y=mx+c

Two lines with slope 1 and m are perpendicular to each other.

So, m1m2=−1 where m1=1 and m2=m......Condition for perpendicular lines

∴m×1=−1

∴m=−1

Put m=−1 in the straight line y=mx+c, we get y=−x+c.

Now, line y=−x+c also passes through the point (7,1) and hence, it should satisfy the line equation.

Put (7,1) in the equation y=−x+c, we get

1=−7+c

∴c=8

Therefore, final equation comes out to be y=−x+8.

Now, find the intersection of both the lines which comes out to be (5,3) which will be a midpoint of the point (7,1) and (a,b) since it is equidistant from both the points.

So, from midpoint formula, we get

2a+7=5 and 2b+1=3

∴a=3,b=5

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