find distance of point p(x,y) from origin
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Ans.
The required distance is

The required distance is
Answered by
1
Given:
Point ( x, y )
Origin ( 0, 0 )
To find:
The distance.
Solution:
By formula
Distance between two points = √(( y2 - y1 )^2 + ( x2 - x1 )^2)
Origin ( 0, 0 ) ( x1, y1 )
Point ( x, y ) ( x2, y2 )
Distance = √(( y - 0 )^2 + ( x - 0 )^2
√(x)^2 + (y)^2
Hence, the distance of a point P(x,y) from the origin is √(x)^2 + (y)^2.
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