Question

find distence beetwen x+5y-9=0 and x+5y+7=0?

Answer 1

Hello users.....

We have given two parallel lines
x+5y-9=0 and x+5y+7 = 0

We have to find the distance between these two lines

Solution:-
We know that

Distance(D) between two parallel lines = | C2 -C1| / √(a² +b² )

Now
By comparing
x+5y-9= ax + by +c1 = 0
and
x+5y+7 = ax + by +c2 = 0

Here
a= 1 ,b= 5 , c1 = -9 ,c2 = 7

Now
D = | c2 -c1 | / √(a² +b² )
= | 7-(-9) |/√(1+5²)
= |7+9| / √(1+25)
= 16 / √26



Hence
the distance between two parallel lines = 16/√26 unit answer

✡✡ Hope it helps ✡✡

Answer 2

Answer:

Step-by-step explanation:

yes he or she is right