Question

find domain and range of f(x)=square root of 12- x 2

Answer 1

$12 - x {}^{2} \geqslant 0 \\ 12 \geqslant x {}^{2} \\ x \leqslant \sqrt{12}$
domain of is square root of 12

Answer 2

Answer:

Ya first things first,

A root should always be positive .

So umm..

root(12-x²)......greater than equals to....0

Squaring both sides,

12-x² ......greater than equals to......0

12......greater than equals to.....x²

x......less (sign changes) than equals to.......root(12)

So umm... the domain is All Real Numbers except root(12)

And the Range should lie between

[0, root 12]

Step-by-step explanation: