Question

find domain and range of f(x)= x/1+x^2
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Answer 1

Answer:

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Answer 2

HEY MATE HERE IS YOUR ANSWER

The domain is x∈R.

The range is y∈(0,1]

Step By Step Explanation:

The denominator is =1+x2

∀x∈R, 1+x2>0

Therefore,

The domain of f(x) is x∈R

To determine the range, proceed as follows

y=11+x2

y(1+x2)=1

y+ yx2=1

yx2=1−y

x2=1−y/y

x=√1−y/y

The range of f(x) is the domain of x

(1−y/y)>0

y∈R*+

1−y≥0

y≤1

Therefore,

The range is y∈(0,1]

graph{1/(1+x^2) [-11.25, 11.25, -5.625, 5.625]}

hope it helps u....

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