find domain of f(x) = (x² + x + 1)^-3/2
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2
Answer:
Given,
f(x)=x2+x−6x2−3x+2
x2+x−6=0
roots of above equation are:
x=−3,2
So, x can't be equal to −3or2
The above points are undefined
The function domain is
x<−3,−3<x<2,x>2
{x:x∈R,x=2,x=−3}
Answered by
1
Answer:
It's right mate which is written above... xd... ..☺☺❤❤✌
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