FIND dy by dx of x²+xy+y²
Sajith:
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2
y = x²+xy+y²
Differentiating both sides w.r.t 'x' we get,
dy/dx = 2x + y + dy/dx. x + 2y. dy/dx
Taking all dy/dx on one side,
dy/dx - dy/dx.x - 2y. dy/dx = (2x - y)
Taking dy/dx common,
dy/dx (1-x-2y) = (2x - y)
dy/dx = (2x - y)/ (1 - x - 2y)
Differentiating both sides w.r.t 'x' we get,
dy/dx = 2x + y + dy/dx. x + 2y. dy/dx
Taking all dy/dx on one side,
dy/dx - dy/dx.x - 2y. dy/dx = (2x - y)
Taking dy/dx common,
dy/dx (1-x-2y) = (2x - y)
dy/dx = (2x - y)/ (1 - x - 2y)
Answered by
0
let it
dy/dx=2x+y+xdy/dx+2ydy/dx
dy/dx(1-x-2y)=2x+y
dy/dx=2x+y/1-x-2y
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