Question

Find dy/dx..✌✌✌above

DERIVATIVE

$<marquee>$ ☠30 points❤☠ ​

Answer 1

Answer:

Step-by-step explanation:

d x^x^x/dx=dy/dx

x^x^x*d/dx(log x(x^x))=y'

[d/dx(x^x)*log x+x^x*d/dx(log x)]  * x^x^x=y'

x^x^x[(x^x*d/dx(logx(X)*log x)+(1/x*x^x)]

=x^x^x(x^x*log x(log x+1)+x^(x-1)

Answer 2

welcome to the concept of differentiation .

this question easily solve by

method of differentiation of logarithm function

⏩I hope it help you ❤️