Find dy/dx for the following function :-y=xlogsinx.
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Answer: xcotx+logsinx
Step-by-step explanation
d/dx(xlogsinx)
This is in the form of (UV) formula (u.d/dX(v)+v.d/dx(u)
x.d/dx(logsinx)+logsinx.d/dx(x)
=x.1/sinx.d/dx(sinx)+logsinx(1)
=x.1/sinx.cosx+logsinx
=xcotx+logsinx
Hope you get this
Thank you
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