the 3rd and 6th terms of an ap are 16 and 37 respectively find the first term and the common difference
Answers
Answered by
4
Answer:
d=-7 a=2
Step-by-step explanation:
a3=16,a6=37
a3= a-2d
16= a-2d .....1
37= a-5d......2
2-1 》 d= -7
substitute d= -7 in .....1
a- 2(-7)=16
a+14=16
a=16-14
a=2
a=2 & d= -7
Answered by
3
Answer:
a = 2. d = 7. Please mark it as brainliest
Step-by-step explanation:
3rd term means
a + 2d equation 1
6th term means
a + 5d equation 2
subtracting equation 1 and 2
a + 2d = 16
- a + 5d = 37
- 3d = -21
3d = 21
d = 21/3
d = 7
substituting d value in equation 1
a + 2d = 16
a + 2(7) = 16
a + 14 = 16
a = 16 - 14
a = 2
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