Question

find dy/dx from y = sin (xˣ)

Answer 1

Hey MATE!

Let us assume x^x = t

Therefore, logt = xlnx

Now differentiating both side we get:

dt/tdx = [x(1/x) + 1(lnx)]

dt/tdx = 1 + lnx

Now we differentiate the whole y.

dy/dx = Cos(x^x) * [1 + lnx]. Answer

Hope it helps

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