find dy÷dx if x sin y + y sin x = 0
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applying product rule
(1.siny+x.cos y. dy/dx) + (dy/dx.sinx + y.cosx)=0
sin y + xcos y.dy/dx + dy/dx.sinx + y.cosx=0
dy/dx(xcos y + sinx) = -sin y - ycos x
dy/dx = -(sin y + ycos x)/(xcos y+ sinx)
(1.siny+x.cos y. dy/dx) + (dy/dx.sinx + y.cosx)=0
sin y + xcos y.dy/dx + dy/dx.sinx + y.cosx=0
dy/dx(xcos y + sinx) = -sin y - ycos x
dy/dx = -(sin y + ycos x)/(xcos y+ sinx)
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