find dy/dx if x + √xy + √y = 1
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Answer:
Hope it helps friend
Step-by-step explanation:
Given x+√xy +y=1
Differentiate w.r.t.x
1+1/2√xy (x dy/dx +y 1)+dy/dx =0
Or (1+y/2√xy)+dy/dx (1+x/2√xy) =0
Or dy/dx =-(1+y/2√xy)/(1+x/2√xy)
Or dy/dx =-(1+√y/2√x)/(1+√x/2√y)
Or dy/dx =-(2√x+√y)(2√y+√x) /4√xy
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