Question

Find
dy/dx if x² + y² = 1
​

Answer 1

Answer:

-x/y

Step-by-step explanation:

differentiating

2x+ 2y dy/dx =0

2y dy/dx = -2x

dy/dx = -2x/ 2y

dy/dx = -x/y

Answer 2

Here's your answer:

$\frac{d}{dx} (y^2+x^2)=\frac{d}{dx} (1)$

$\frac{d}{dx} (x^2)+\frac{d}{dx}(y^2) =0$

$2x+2y.\frac{d}{dx} (y)=0$

$2y.\frac{dy}{dx} +2x=0$

$2(y.\frac{dy}{dx} +x)=0$

$y.\frac{dy}{dx} +x=0$

$y.\frac{dy}{dx} =-x$

$\frac{dy}{dx} =-\frac{x}{y}$

Hope it helps

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