Question

Find the side of a square whose perimeter is 120 cm.
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Find the circumference of the circle whose diameter is 2.8m.


Find the area of an equilateral triangle whose each side is 10 cm.​

Answer 1

Answer:

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Answer 2

Answer:

a) Perimeter of square = 4 × sides

120cm = 4 × side

side = 30cm

b) diameter = 2.8cm

radius = d/2 = 1.4cm

circumference = 2πr

= 2 × 22/7 × 1.4

= 2 × 22 × 0.2

= 8.8cm

c) Each side of equilateral Δ = 10cm

s = a+b+c/2

s = 10+10+10/2

s = 15

Area Δ =

$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \geqslant \sqrt{15 \times 5 \times 5 \times 5 } \\ \\ = \geqslant \sqrt{1875}$