Question

find dy/dx if xcosy+ycosx=0​

Answer 1

Answer:

Step-by-step explanation:

We know that d/dx (uv)= u. dv/dx + v. du/dx

x cos y + y cos x = 0

Differentiate w.r.t.x

x.(-sin y).dy/dx + cosy

+y.(-sin x) + cos x. dy/dx = 0

-x.siny.dy/dx + cos y - y sin x+cos x.dy/dx=0

dy/dx . (cos x - x sin y)=y sin x - cos y

So dy/dx = (y sin x - cos y)/(cosx - x sin y)