Find dy/dx if y=cos(x+y)
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Answered by
1
Hi friend,
Given,
Dy/DX= cos( x+y)
With respect to x differentiate,
Dy/DX= -xsin (x+y)... y' = - 1 + 1/[1 + √(1-y²) ]
Hope this helps you..
Please mark it as brainliest answer...
Given,
Dy/DX= cos( x+y)
With respect to x differentiate,
Dy/DX= -xsin (x+y)... y' = - 1 + 1/[1 + √(1-y²) ]
Hope this helps you..
Please mark it as brainliest answer...
Answered by
2
y' = - sin(x+y) (1+y')
y' [1 + sin(x+y) ] = - sin(x+y)
y' = - sin(x+y) / [ 1 + sin(x+y) ] = - 1 + 1/[1 + sin (x+y) ]
y' = - 1 + 1/[1 + √(1-y²) ]
y' [1 + sin(x+y) ] = - sin(x+y)
y' = - sin(x+y) / [ 1 + sin(x+y) ] = - 1 + 1/[1 + sin (x+y) ]
y' = - 1 + 1/[1 + √(1-y²) ]
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