find dy/dx if y =log (sin x^2)
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2sinx cosx/(sinx^2) = 2cotx
ddasddas:
sorry but answer is wrong
the answer is 2x.cot x^2
I thought the question is (sinx)^2 but it is actually x^2. so my answer is wrong
Answered by
1
dy/dx= cosx^2 *2x/sinx^2
= cotx^2 *2x
= cotx^2 *2x
prove it in the chart
sry i couldn't understand u
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