Question

find dy/dx if y=u^3 + 2u and u= x^2 + 5

Answer 1

Answer:

$\frac{dy}{du} = 3 {u}^{2} + 2 \\ \frac{du}{dx} = 2x \\ \\ so \: \frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx} \\ = (3 {u}^{2} + 2) \times 2x \\ = 3( { {x}^{2} + 5) }^{2} + 2) \times 2x$

Answer 2

Answer:

this is correct......................