Find dy/dx if y=x+1/x-1
Answers
Answered by
11
Answer:
-2/(x-1)^2
Step-by-step explanation:
y=x+1/x-1
Now differentiating with respect to x.
dy/dx = [(x-1)× d/dx (x+1) - (x+1)× d/dx(x-1)] / (x-1)^2
dy/dx = [(x-1)×1 - (x+1)×1] / (x-1)^2 [because d/dx x =1 , d/dx 1 = 0]
dy/dx = [ x-1-x-1] / (x-1)^2
dy/dx = -2/ (x-1)^2.
Answered by
1
Answer:
y=x+1/x-1
dy/dx =(x-1).1-(x+1).1/(x-1)^2
=x-1-x-1/(x-1)^2 dy/ dx =-2/(x-1)^2
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