Question

Find dy/dx in the following: y = x + sin x + e^x - log x​

Answer 1

Answer:

$\frac{dy}{dx} \: = 1 + \cos(x) + {e}^{x} - \frac{1}{x}$

Step-by-step explanation:

Given :

$y \: = x \: + \sin(x) + {e}^{x} - log(x)$

$\frac{dy}{dx} = \: 1 \: + \cos(x) + {e}^{x} - \frac{1}{x}$