Question

Find dy/dx of log (x raise to x + cosec raise 2 x)

Answer 1

Answer:

dy/dx ={1+logx-cosec²x.cotx}

Step-by-step explanation:

to find dy/dx of

logx^x +cosec²x

y=xlogx+cosec²x

:- logn^m =mlogn

Using product rule

dy/dx =xd/dx logx +logx d/dx x +d/dx cosec²x

dy/dx =x×1/x +logx +2cosecx ×(-cosecx×cotx)

:-d/dx cosecx =-cosecx.cotx

:- d/dx logx = 1/x

dy/dx =(1+logx)-2cosec²x.cotx

is the Answer..

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