Question

Find dy/dx of the above question​

Answer 1

Explanation:

2y^2-1/2×1+0= 2y/2= y so y is the answee

Answer 2

Explanation:

x=y^2/2y+1

differentiate with respect to x

1=(2y+1).2ydy/dx- y^2(2dy/dx) / (2y+1)^2

(2y+1)^2=4y^2dy/dx+2ydy/dx-4y^2dy/dx

=2ydy/dx

dy/dx= (2y+1)^2/2y