Question

find dy/dx of the following:
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Answer 1

Answer:

hii...

Step-by-step explanation:

given here x^y=e^(x-y).

taking log both sides ....

then...

y log( x)= (X-y) log(e).=(X-y)

. because [ log e =1.]

so...

y= x/(1+log x)

differentiate both sides with respect to x....

then..

day/dx= [(1+log)- x(0+1/x)]/(1+log x)^2.

dy/dx=log x /(log e + log x)^2

___answer will be ______________________

dy/dx= log x/(log ex)^2.

_________________________

because (log xy=log x+log y).

i hopes its helps u.

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