Question

find dy/dx of x^3.logx

Answer 1

Use uv rule, i.e. d(uv)/dx=
v(du/dx)+u(dv/dx)
dy(x^3logx)/du =
x^3(d(log)/dx))+logx(d(x^3))
=x^3(1/x)+logx(3x^2)
=x^2+3x^2(logx)
=x^2(1+3logx) =x^2(1+logx^3)

Hope it helps!!
Pls mark it as the brainliest.

Answer 2

heya 

let y = x³.logx

we will apply product rule while solving this problem since it is product of two functions 

so 

dy/dx = d/dx(x³logx)
        = logx d/dx(x³) + x³ d/dx(logx)  :   { we know d/dx(x^n) =  nx^n-1, d/dx(logx) = 1/x   apply it here

=  logx .( 3x²) + x³.1/x 
= 3x²logx + x²
=x²(logx³ + 1) 

i hope this will help you