Question

Find dy/dx

$2\sqrt{cotx {?}^{2} }$
​

Answer 1

Answer:

dx

d

[2

cot(x

2

)

]

=2.

2

cot(x

2

)

1

×

dx

d

[cot(x

2

)]

=

cos(x

2

)

sin(x

2

)

×−cosec

2

(x

2

)×

dx

d

(x

2

)

=

cos(x

2

)

sin(x

2

)

×−

sin

2

(x

2

)

1

×(2x)

=

cosx

2

sinx

2

sinx

2

−2x

=

2sinx

2

cosx

2

sinx

2

−2

2

x

=

sinx

2

sin(2x

2

)

please mark this as brainlist