Question

Find dy/dx when x = cos ( log t ) and y = log ( cos t )​

Answer 1

Answer:

dx/dt = -sin(log t)(1/t).

dy/dt = {1/(cos t)}(-sin t)

then,

dy/dx = (dy/dt)/(dx/dt) = (t sin t)/{(cos t) sin(log t)}

=>dy/dx = (t tan t)/sin(log t).