Question

find dy/dx when y=log(4/x)
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Answer 1

Answer:

y=log(4/x)

differentiating both sides, we get

dy/dx=d/dx[log(4/x)]

dy/dx=(x/4)d/dx(4x^-1)

dy/dx=(x/4)4(-1)(x^-2)

dy/dx=-x(x^-2)

dy/dx=-x^-2+1

dy/dx=-x^-1