find dy/dx,when y=(x2+3)(x4-8)
(fast please)
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Answer:
6x^5 + 12x^3 - 16x
Explanation:
Let's use the product rule
(x^2 + 3)*dy/dx(x^4 - 8) + dy/dx(x^2+3)*(x^4-8)
(x^2 + 3) * (4x^3) + (2x)*(x^4 - 8)
= 4x^5 + 12x^3 + 2x^5 - 16x
= 6x^5 + 12x^3 - 16x
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