Physics, asked by avirajmeet, 9 months ago

find dy/dx,when y=(x2+3)(x4-8)

(fast please)​

Answers

Answered by tosushilpandey
2

Answer:

6x^5 + 12x^3 - 16x

Explanation:

Let's use the product rule

(x^2 + 3)*dy/dx(x^4 - 8) + dy/dx(x^2+3)*(x^4-8)

(x^2 + 3) * (4x^3) + (2x)*(x^4 - 8)

= 4x^5 + 12x^3 + 2x^5 - 16x

= 6x^5 + 12x^3 - 16x

Similar questions