Question

FInd dy/dx where y= a^x + log x +a^2e^x

Answer 1

Answer:

a^x/loga + 1/x + a²e^x

Explanation:

derivative of a^x = a^x/loga

derivative of log x = 1/x

derivative of a²e^x is a² e^x since a² is a constant it moves out of the derivative leaving only the derivative of e^x which is e^x

hope it helps

pls mark as brainliest

Answer 2

Answer:

dy/dx=a^x.loga+(1/x)+a^2*e^x

Explanation:

d(a^x)/dy=(a^x)*loga

d(logx)/dy=1/x

d(a^2*e^x)/dx=a^2*e^x where a^2 is constant