Find dy/dx with respect to x
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2x - 1/2x^3 .....may be not sure
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chethangowda:
it's diffrenciation
wrong
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y = (2x + 1/x)^2
dy/dx = d(2x + 1/x)^2/dx
by using formula
d[f(x)^n]/dx = n*f(x) * d[f(x)]
dy/dx = 2*(2x + 1/x)^2-1 * d(2x + 1)/dx
= 2(2x + 1) * d(2x)/dx + d(1)/dx
= 2(2x + 1)*2 + 0
=4*(2x + 1)
this is ur answer hope it is correct.
dy/dx = d(2x + 1/x)^2/dx
by using formula
d[f(x)^n]/dx = n*f(x) * d[f(x)]
dy/dx = 2*(2x + 1/x)^2-1 * d(2x + 1)/dx
= 2(2x + 1) * d(2x)/dx + d(1)/dx
= 2(2x + 1)*2 + 0
=4*(2x + 1)
this is ur answer hope it is correct.
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