find dy/dx x2y+y2x=a2
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x^2 × dy/dx + y ×2x + y^2 ×1 + x× 2y dy/dx =0
2xy +y^2 + dy/dx(x^2 + 2xy) =0
dy/dx(x^2 + 2xy) = -(2xy + y^2)
dy/dx = -(2xy + y^2)/ (x^2 +2xy) is answer
2xy +y^2 + dy/dx(x^2 + 2xy) =0
dy/dx(x^2 + 2xy) = -(2xy + y^2)
dy/dx = -(2xy + y^2)/ (x^2 +2xy) is answer
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may b it'll help u....
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