Question

find dy/dx y=(x-sinx)(1+cos x)​

Answer 1

Answer:

y= (x-sinx )(1+cosx)

dy/dx= dy/dx (x-sinx) (1+cosx)

dy/dx = (x-sinx ) dy/dx (1+cosx) + (1+cosx) dy/dx (x-sinx)

dy/dx = (x-sinx) (0-sinx) + (1+cosx) (1-cosx)

dy/dx = -xsinx + sin^2x + ( 1- cos^2x)

dy/dx =-xsinx +sin^2x + sin^2x

dy/dx = -xsinx + 2sin^2x

dy/dx = sinx(2sinx-x)