find electric current drawn from battery of emf 12v
explain how to do
explain with formulas and process also
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Solution: We have use Kirchoff's rules 1st & 2nd.
We have use Kirchoff's rules 1st & 2nd.In wire mesh (loop) AFEDA, we have,
→ +12 V - I₂ × 4Ω - (I₁ + I₂) × 3Ω = 0
→ 12 - 7 I₂ -3 I₁ = 0
→ 7 I₂ + 3 I₁ = 12 ....... (1)
In wire mesh (loop) ABCDA, we have,
→ +12 V - 5 V - I₁ × 2Ω - (I₁ + I₂) × 3Ω = 0
→ 7 - 5I₁ -3I₂ = 0
→ 3 I₂ + 5I₁ = 7 ....... (2)
Multiplying eq.(1) by 3, we get,
→ 21 I₂ + 9 I₁ = 36.....(3)
And multiplying eq.(2) by 7, we get,
→ 21 I₂ + 35 I₁ = 49.....(4)
Now substracting eq.(3) from eq.(4), we get,
→ 26 I₁ = 13
→ I₁ = 13/26= 0.5
Now substituting value of I₂ in eq.(2), we get value of I₁,
→ 3 I₂ + 5 × 0.5 = 7
→ 3 I₂ = 7 - 2.5
→ I₂ = 4.5/3 = 1.5
Therefore, I₁ + I₂ = 2
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