Question

Find equation line through (0,3) and perpendicular to the line joining points (-3,2)and (9,1)​

Answer 1

Answer:

12x - y +3 =0

Step-by-step explanation:

Let the slope of the required line be "m".

From the given data , we can find the slope of the line perpendicular to the line of slope m.

So, perpendicular slope = $\frac{2-1}{-3-9}$ = -1/12.

And the product of the slopes of lines perpendicular to each other =-1

Therefore,    (m) (-1/12) =-1

                => m = 12  

Now, we have the slope and the point .

So, applying point slope form, we get

                           $y-y_{1}=m(x-x_{1} )$  and   here,  m = 12

                                                                               $(x_{1} ,y_{1})$ = (0,3)

                    =>  y - 3 = 12(x - 0)

                    =>  y - 3 = 12 x

                    =>  12x - y +3 =0   is the equation of the required line.