Question

Rationalise the denominator of
1 / 7+3√2​

Answer 1

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Answer 2

Hope this helps you ;)

$\frac{1}{7 + 3 \sqrt{2} }$

$= \frac{1}{7 + 3 \sqrt{2} } \times \frac{(7 - 3 \sqrt{2}) }{(7 - 3 \sqrt{2}) }$

$= \frac{7 - 3 \sqrt{2} }{ {(7)}^{2} - {(3 \sqrt{2}) }^{2} }$

$= \frac{7 - 3 \sqrt{2} }{49 - 18}$

$= \frac{7 - 3 \sqrt{2} }{31}$