Question

Find equation of circle with centre ( 0,2) and r = 2

Answer 1

Equation of standard circle i.e circle having its centre at origin is 
x2+y2=r2 
here r is the radius 
Now if the circle does not have its centre at origin 
then 
if it is having its cente at poin (X1,Y1)
then 
equation of circle can be written as 
(x−X1)2+(y−Y1)2=r2 
then for now for above question points are (2,-3)
and radius is 3
then equation is 
(x−2)2+(y−(−3))2=9

PLZ MARK AS BRAINLIST

Answer 2

Hey!
____


___________________________________________________________


Ques. → Find Equation of circle with Centre ( 0 , 2 ) and radius = 2 units .


Ans. → We know that the equation of a circle is given by the formula ,


$= > \sqrt{(x - h) {}^{2} + (y - k) {}^{2} } = r$

★ Squaring both the sides we have ,



=> ( x - h )² + ( y - k )² = r²


★Here h = 0 , k = 2 and r = 2 . Put the values →


=> ( x - 0 )² + ( y - 2 )² = 2²


=> x² + y² + 4 -4y = 4


=> x² + y² - 4y = 0


°•° The Equation of the circle is → x² + y² - 4y = 0 ✔


_____________________________________________