Question

Find equation of line if it is
perpendicular to a line with
-6 and
y-intercept is ½​

Answer 1

Answer:

x - 6y + 3 = 0

Step-by-step explanation:

If two lines are ⊥, product of their slope is - 1.

Let the slope of required line be m₁.

⇒ (-6)m₁ = - 1      ⇒ m₁ = 1/6

Equation of the required line is:

⇒ y = mx + c

⇒ y = (1/6)x + 1/2

⇒ y = (x + 3)/6

⇒ 6y = x + 3

⇒ x - 6y + 3 = 0

Answer 2

Given :-

Perpendicular to a line with -6 and y-intercept is ½​

To Find :-

Equation of the line

Solution :-

Let us assume the slope as x

$\sf -6\times x = -1$

$\sf x = \dfrac{-1}{-6}$

$\sf x = \dfrac{1}{6}$

Now,

By using the formula

y = mx + c

But here we used m as x

$\sf y = \dfrac{1}6x+ \dfrac{1}{2}$

$\sf y = \dfrac{1x + 3}{6}$

$\sf 6(y) = x+3$

$\sf6y=x+3$

$\sf x - 6y+3$