Question

Find equation of line passing through the point (4,5) and perpendicular to 7x-5y=420

Answer 1

Answer:

5/7x+y-35/6=0

Step-by-step explanation:

slope of perpendicular line=coefficient of x/coefficient of y=7/5

slope of line(m)=7/5×m= -1

so,

m=-5/7

one point form

(y-y1)=m(x-x1)

(X1,y1)=(4,5)

(y-5)=-5/7(x-4)

y-5=-5/7x+5/6

5/7x-5/6+y-5=0