Find equation of line perpendicular to the line x-3y+3=0 and passing through the point (1,-2)
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Thus, b = -4, and so the equation of the line perpendicular to 2x - 3y = 13 is y = (-3/2) - 4
Answered by
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Answer:
Answer:
Thus, b = -4, and so the equation of the line perpendicular to 2x - 3y = 13 is y = (-3/2) - 4
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