Question

Find equation of line which passing through point 3,-2 and making angle 60 with positive direction of y axis

Answer 1

The equation of line is $y=\dfrac{1}{\sqrt{3}}x-\sqrt{3}-2$

Step-by-step explanation:

The line makes angle 60° with positive direction of y-axis.

Slope = tan(90-Ф)

Slope = tan 30°

Slope = $\dfrac{1}{\sqrt{3}}$

Passing point: (3,-2)

Equation of line:

$y+2=\dfrac{1}{\sqrt{3}}(x-3)$

$y=\dfrac{1}{\sqrt{3}}x-\sqrt{3}-2$

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